## Intermediate Algebra (12th Edition)

$-\frac{6}{23}$
We can plug in the given values to the expression in order to evaluate. $\frac{8k+2m^{2}}{r-2}=\frac{8(-3)+2(-3)^{2}}{(25)-2}=\frac{8(-3)+2(-3\times-3)}{(25)-2}=\frac{8(-3)+2(9)}{(25)-2}=\frac{-24+18}{25-2}=\frac{-6}{23}=-\frac{6}{23}$