Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter R - Test - Chapter R Test: 21

Answer

$-\frac{6}{23}$

Work Step by Step

We can plug in the given values to the expression in order to evaluate. $\frac{8k+2m^{2}}{r-2}=\frac{8(-3)+2(-3)^{2}}{(25)-2}=\frac{8(-3)+2(-3\times-3)}{(25)-2}=\frac{8(-3)+2(9)}{(25)-2}=\frac{-24+18}{25-2}=\frac{-6}{23}=-\frac{6}{23}$
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