Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter R - Test - Chapter R Test: 12

Answer

$\dfrac{16}{7}$

Work Step by Step

Using order of operations, the given expression, $ \dfrac{-2[3-(-1-2)+2]}{\sqrt{9}(-3)-(-2)} ,$ simplifies to \begin{array}{l}\require{cancel} \dfrac{-2[3-(-3)+2]}{3(-3)+2} \\\\= \dfrac{-2[3+3+2]}{-9+2} \\\\= \dfrac{-2[8]}{-7} \\\\= \dfrac{-16}{-7} \\\\= \dfrac{16}{7} .\end{array}
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