Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter R - Section R.4 - Properties of Real Numbers - R.4 Exercises: 31

Answer

$-2k+15$

Work Step by Step

The distributive property holds that $a(b+c)=ab+ac$ (for real numbers $a$, $b$, and $c$). We are given the expression $3(k+2)-5k+6+3$. We can use the distributive property to simplify the terms in parentheses and combine like terms. $3(k+2)-5k+6+3=(3\times k)+(3\times2)-5k+6+3=3k+6-5k+6+3=(3-5)k+(6+6+3)=(-2)k+(15)=-2k+15$
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