Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter R - Section R.3 - Exponents, Roots, and Order of Operations - R.3 Exercises: 94

Answer

$\frac{29}{32}$

Work Step by Step

We are given the expression $\frac{7y-5x}{2w}$. We can plug in the given values to solve for the given expression. $\frac{7y-5x}{2w}=\frac{7(\frac{1}{2})-5(-\frac{3}{4})}{2(4)}=\frac{\frac{7\times1}{2}-(\frac{5\times-3}{4})}{8}=\frac{\frac{7}{2}-(\frac{-15}{4})}{8}=\frac{\frac{7}{2}+\frac{15}{4}}{8}=\frac{\frac{7\times2}{2\times2}+\frac{15}{4}}{8}=\frac{\frac{14}{4}+\frac{15}{4}}{8}=\frac{\frac{14+15}{4}}{8}=\frac{\frac{29}{4}}{8}=\frac{29}{4}\times\frac{1}{8}=\frac{29}{32}$
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