## Intermediate Algebra (12th Edition)

$\frac{33}{4}$
We are given the expression $w-6x+5y-3z$. We can plug in the given values to solve for the given expression. $w-6x+5y-3z=(4)-6(-\frac{3}{4})+5(\frac{1}{2})-3(1.25)=4-(\frac{6\times-3}{4})+\frac{5\times1}{2}-3.75=4-(-\frac{18}{4})+\frac{5}{2}-3.75=4+\frac{18}{4}+\frac{5}{2}-3.75$ Next, we can further simplify by expressing each term as a fraction with a denominator of 4. $\frac{16}{4}+\frac{18}{4}+\frac{5\times2}{2\times2}-\frac{11}{4}=\frac{16}{4}+\frac{18}{4}+\frac{10}{4}-\frac{11}{4}=\frac{16+18+10-11}{4}=\frac{33}{4}$