Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter R - Section R.3 - Exponents, Roots, and Order of Operations - R.3 Exercises: 86

Answer

$\frac{27}{92}$

Work Step by Step

We are given that $a=-3$, $b=64$, and $c=6$. Therefore, $\frac{3c+a^{2}}{2b-6c}=\frac{3(6)+(-3)^{2}}{2(64)-6(6)}=\frac{18+9}{128-36}=\frac{27}{92}$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.