Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter R - Section R.3 - Exponents, Roots, and Order of Operations - R.3 Exercises: 83

Answer

-96

Work Step by Step

We are given that $a=-3$, $b=64$, and $c=6$. Therefore, $4a^{3}+2c=4(-3)^{3}+2(6)=4(-27)+12=-108+12=-96$
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