Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter R - Section R.3 - Exponents, Roots, and Order of Operations - R.3 Exercises: 81

Answer

17

Work Step by Step

We are given that $a=-3$, $b=64$, and $c=6$. Therefore, $\sqrt b+c-a=\sqrt 64+6-(-3)=8+6+3=14+3=17$. We know that $\sqrt 64=8$, because $8^{2}=64$.
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