Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter R - Section R.3 - Exponents, Roots, and Order of Operations - R.3 Exercises - Page 30: 72

Answer

$-1$

Work Step by Step

Using order of operations, the given expression, $ -12\left(-\dfrac{3}{4}\right)-(6\cdot5\div3) ,$ simplifies to \begin{array}{l}\require{cancel} -\cancel{12}^3\left(-\dfrac{3}{\cancel{4}}\right)-(30\div3) \\\\= 9-10 \\\\= -1 .\end{array}
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