## Intermediate Algebra (12th Edition)

$\frac{100}{121}$
$\sqrt \frac{100}{121}=\frac{10}{11}$, which we know because $(\frac{10}{11})^{2}=\frac{10}{11}\times\frac{10}{11}=\frac{10\times10}{11\times11}=\frac{100}{121}$