Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter R - Section R.2 - Operations on Real Numbers - R.2 Exercises: 97

Answer

$-\frac{22}{45}$

Work Step by Step

$-\frac{7}{30}+\frac{2}{45}-\frac{3}{10}=-\frac{7\times3}{30\times3}+\frac{2\times2}{45\times2}-\frac{3\times9}{10\times9}=-\frac{21}{90}+\frac{4}{90}-\frac{27}{90}=\frac{-21+4-27}{90}=\frac{-44}{90}=-\frac{44}{90}$ Further simplification: $-\frac{44}{90}=-\frac{44\div2}{90\div2}=-\frac{22}{45}$
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