Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter R - Section R.2 - Operations on Real Numbers - R.2 Exercises: 96

Answer

$-\frac{53}{45}$

Work Step by Step

$-\frac{11}{15}-\frac{4}{9}=-(\frac{11}{15}+\frac{4}{9})=-(\frac{11\times3}{15\times3}+\frac{4\times5}{9\times5})=-(\frac{33}{45}+\frac{20}{45})=-(\frac{33+20}{45})=-(\frac{53}{45})=-\frac{53}{45}$
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