Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter R - Section R.2 - Operations on Real Numbers - R.2 Exercises: 95

Answer

$-\frac{19}{24}$

Work Step by Step

$-\frac{3}{8}-\frac{5}{12}=-(\frac{3}{8}+\frac{5}{12})=-(\frac{3\times3}{8\times3}+\frac{5\times2}{12\times2})=-(\frac{9}{24}+\frac{10}{24})=-(\frac{9+10}{24})=-(\frac{19}{24})=-\frac{19}{24}$
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