Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter R - Section R.2 - Operations on Real Numbers - R.2 Exercises: 94

Answer

$\frac{35}{48}$

Work Step by Step

$-\frac{1}{12}+\frac{13}{16}=\frac{13}{16}-\frac{1}{12}=\frac{13\times3}{16\times3}-\frac{1\times4}{12\times4}=\frac{39}{48}-\frac{4}{48}=\frac{39-4}{48}=\frac{35}{48}$
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