Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter R - Section R.2 - Operations on Real Numbers - R.2 Exercises: 93

Answer

$\frac{17}{36}$

Work Step by Step

$-\frac{1}{9}+\frac{7}{12}=\frac{7}{12}-\frac{1}{9}=\frac{7\times3}{12\times3}-\frac{1\times4}{9\times4}=\frac{21}{36}-\frac{4}{36}=\frac{21-4}{36}=\frac{17}{36}$
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