Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter R - Section R.2 - Operations on Real Numbers - R.2 Exercises: 91

Answer

$\frac{17}{18}$

Work Step by Step

$\frac{1}{6}-(-\frac{7}{9})=\frac{1}{6}+\frac{7}{9}=\frac{1\times3}{6\times3}+\frac{7\times2}{9\times2}=\frac{3}{18}+\frac{14}{18}=\frac{3+14}{18}=\frac{17}{18}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.