## Intermediate Algebra (12th Edition)

$\frac{25}{102}$
$-\frac{10}{17}\div(-\frac{12}{5})=-\frac{10}{17}\times-\frac{5}{12}=\frac{-10\times-5}{17\times12}=\frac{50}{204}$ $\frac{50}{204}=\frac{50\div2}{204\div2}=\frac{25}{102}$ Both numbers being multiplied have the same sign, so the resulting product is positive.