## Intermediate Algebra (12th Edition)

$\frac{1}{4}$
$\frac{4}{3}(-\frac{9}{20})(-\frac{5}{12})=\frac{4\times-9\times-5}{3\times20\times12}=\frac{180}{720}$ $\frac{180}{720}=\frac{180\div180}{720\div180}=\frac{1}{4}$ The two negative signs in the numerator cancel out, so the resulting product is positive.