Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter R - Section R.2 - Operations on Real Numbers - R.2 Exercises: 54

Answer

$\frac{13}{2}=6.5$

Work Step by Step

In order to find the distance between two points, we can find the absolute value of the difference of the numbers (taken in either order). $E=-\frac{3}{2}$ $C=5$ $|(-\frac{3}{2}-5)|=|-(\frac{3}{2}+5)|=|-(\frac{3}{2}+\frac{10}{2})|=|-(\frac{13}{2})|=|-\frac{13}{2}|$ The absolute value of a number $a$ is equal to $a$ if $a\geq0$ and is equal to $-a$ if $a\lt0$. $-\frac{13}{2}\lt0$, so $|-\frac{13}{2}|=-(-\frac{13}{2})=\frac{13}{2}$ Therefore, the distance between the two points is $\frac{13}{2}=6.5$.
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