Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter R - Section R.2 - Operations on Real Numbers - R.2 Exercises - Page 20: 46

Answer

$-\frac{1}{8}$

Work Step by Step

$(-\frac{5}{8}+\frac{1}{4})-(-\frac{1}{4})=(-\frac{5}{8}+\frac{1\times2}{4\times2})-(-\frac{1}{4})=(-\frac{5}{8}+\frac{2}{8})-(-\frac{1}{4})=(\frac{2}{8}+(-\frac{5}{8})-(-\frac{1}{4})=(\frac{2+(-5)}{8})-(-\frac{1}{4})=-\frac{3}{8}-(-\frac{1}{4})$ $-\frac{3}{8}-(-\frac{1}{4})=-\frac{3}{8}+\frac{1}{4}=-\frac{3}{8}+\frac{1\times2}{4\times2}=-\frac{3}{8}+\frac{2}{8}=\frac{2}{8}+(-\frac{3}{8})=\frac{2+(-3)}{8}=-\frac{1}{8}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.