Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter R - Section R.2 - Operations on Real Numbers - R.2 Exercises: 27

Answer

$\frac{67}{30}$

Work Step by Step

$\frac{9}{10}-(-\frac{4}{3})=\frac{9}{10}+\frac{4}{3}=\frac{9\times3}{10\times3}+\frac{4\times10}{3\times10}=\frac{27}{30}+\frac{40}{30}=\frac{27+40}{30}=\frac{67}{30}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.