## Intermediate Algebra (12th Edition)

Published by Pearson

# Chapter R - Section R.1 - Basic Concepts - R.1 Exercises: 42

-.16, .16

#### Work Step by Step

The additive inverse of a number $a$ is $-a$. Therefore, the additive inverse of .16 is $-(.16)=-.16$. The absolute value of a number $a$ is equal to $a$ if $a\geq0$ and is equal to $-a$ if $a\lt0$. Therefore, $|.16|=.16$.

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