#### Answer

2

#### Work Step by Step

We know that logarithms with base $e$ are natural logarithms, and $ln(x)$ is equivalent to $log_{e}(x)$.
Therefore, $ln(e^{2})=log_{e}e^{2}$.
We know that for all positive numbers $a$ (where $a\ne1$), and all positive numbers $x$, $y=log_{a}x$ means the same as $x=a^{y}$.
Therefore, $log_{e}e^{2}=2$, because $e^{2}=e^{2}$.