Answer
2.6601
Work Step by Step
We know that logarithms to base 10 are common logarithms, and $log_{10}x$ is equivalent to $log(x)$.
Therefore, $log(457.2)=log_{10}457.2$.
We know that for all positive numbers $a$ (where $a\ne1$), and all positive numbers $x$, $y=log_{a}x$ means the same as $x=a^{y}$.
Therefore, $log_{10}457.2\approx2.6601$, because $10^{2.6601}\approx457.2$.