Answer
TRUE
Work Step by Step
Using the properties of logarithms, the left-hand expression, $
\log_6 60-\log_6 10
$, is equivalent to
\begin{align*}
&
\log_6 \dfrac{60}{10}
&(\text{use }\log_b \dfrac{x}{y}=\log_b x-\log_b y)
\\\\&=
\log_6 6
\\\\&=
1
&(\text{use }\log_b b=1)
.\end{align*}
Thus, the left-hand expression is equivalent to the given right-hand expression. Hence, the given statement is true.
