Answer
False; $log_{b}xy=log_{b}x+log_{b}y$
Work Step by Step
We know that $log_{b}xy=log_{b}x+log_{b}y$ (where $x$, $y$, and $b$ are positive real numbers and $b\ne1$).
Therefore, the given statement is false. In
$log_{b}xy\ne log_{b}(x+y)$
Instead, $log_{b}xy=log_{b}x+log_{b}y$.