Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 9 - Section 9.3 - Logarithmic Functions - 9.3 Exercises: 80

Answer

-1

Work Step by Step

For any positive real number $b$ (such that $b\ne1$), we know that $log_{b}b^{r}=r$ (as long as $r\gt0$). For $log_{6}\frac{1}{6}$: We know that $6^{-1}=\frac{1}{6}$, so we can replace $\frac{1}{6}$ with $6^{-1}$. Therefore, $log_{6}\frac{1}{6}=log_{6}6^{-1}=-1$.
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