Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 9 - Section 9.3 - Logarithmic Functions - 9.3 Exercises: 48

Answer

{$\frac{1}{2}$}

Work Step by Step

For all positive numbers $a$, where $a\ne1$, and all positive numbers $x$, we know that $y=log_{a}x$ means the same as $x=a^{y}$. Therefore, $log_{x}64=-6$ means the same as $x^{-6}=64$. We know that $x=\frac{1}{2}$, because $\frac{1}{2}^{-6}=64$.
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