Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 9 - Section 9.3 - Logarithmic Functions - 9.3 Exercises: 36

Answer

-2.0478

Work Step by Step

For all positive numbers $a$, where $a\ne1$, and all positive numbers $x$, we know that $y=log_{a}x$ means the same as $x=a^{y}$. Therefore, $log_{\frac{1}{5}}27=x$ means the same as $\frac{1}{5}^{x}=27$. By using a calculator to approximate, we know that $x=-2.0478$, because $\frac{1}{5}^{-2.0478}=27$.
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