Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 8 - Section 8.5 - Graphs of Quadratic Functions - 8.5 Exercises: 9

Answer

$(1,0)$

Work Step by Step

$\bf{\text{Solution Outline:}}$ To find the vertex of the given quadratic function, $ f(x)=(x-1)^2 ,$ convert the function in the form $f(x)=a(x-h)^2+k.$ Once in this form, the vertex is located at $(h,k).$ $\bf{\text{Solution Details:}}$ In the form $f(x)=a(x-h)^2+k,$ the function above is equivalent to \begin{array}{l}\require{cancel} f(x)=(x-1)^2+0 .\end{array} In the function above, $h= 1 $ and $k= 0 .$ Hence, the vertex is \begin{array}{l}\require{cancel} (1,0) .\end{array}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.