## Intermediate Algebra (12th Edition)

Published by Pearson

# Chapter 8 - Section 8.4 - Formulas and Further Applications - 8.4 Exercises: 22

#### Answer

$g=\dfrac{kl}{p^2}$

#### Work Step by Step

$\bf{\text{Solution Outline:}}$ To solve the given equation, $p=\sqrt{\dfrac{kl}{g}} ,$ in terms of $g ,$ square both sides. Then use the properties of equality to isolate the variable. $\bf{\text{Solution Details:}}$ Squaring both sides, the equation above is equivalent to \begin{array}{l}\require{cancel} (p)^2=\left( \sqrt{\dfrac{kl}{g}} \right)^2 \\\\ p^2=\dfrac{kl}{g} .\end{array} Using the properties of equality, the equation above is equivalent to \begin{array}{l}\require{cancel} g(p^2)=\left( \dfrac{kl}{g} \right) g \\\\ gp^2=kl \\\\ g=\dfrac{kl}{p^2} .\end{array}

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