## Intermediate Algebra (12th Edition)

$x=\pm\sqrt{a^2+36}$
$\bf{\text{Solution Outline:}}$ To find the solutions of the given equation, $x^2-a^2-36=0 ,$ isolate first the squared variable. Then take the square root of both sides ((Square Root Property). $\bf{\text{Solution Details:}}$ Using the properties of equality to isolate $x$, the given equation is equivalent to \begin{array}{l}\require{cancel} x^2-a^2-36=0 \\\\ x^2=a^2+36 .\end{array} Taking the square root of both sides, the equation above is equivalent to \begin{array}{l}\require{cancel} x=\pm\sqrt{a^2+36} .\end{array}