Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 8 - Section 8.1 - The Square Root Property and Completing the Square - 8.1 Exercises - Page 511: 3

Answer

It is incorrect to equate each factor of the equation $(x-2)(x+1)=5$ to $5$. The Zero Product Property can only be used if the factors are equal to $0.$

Work Step by Step

In the given equation, $x^2-x-2=5,$ the right side of the equation is not equal to zero. Hence, the left side cannot be factored and then the factors equated to $5$. This method can only be done if the equation is equal to zero. The correct method is to transpose $5$ to the left side and then to combine with $-2.$ Then the resulting equation can be solved by factoring (if factorable) or by the Quadratic Formula.
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