## Intermediate Algebra (12th Edition)

$x=\pm\sqrt{19}$
$\bf{\text{Solution Outline:}}$ To solve the given equation, $x^2=19 ,$ take the square root of both sides (Square Root Property). $\bf{\text{Solution Details:}}$ Taking the square root of both sides (Square Root Property), the equation above is equivalent to \begin{array}{l}\require{cancel} x=\pm\sqrt{19} .\end{array}