Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 7 - Section 7.7 - Complex Numbers - 7.7 Exercises: 10

Answer

1

Work Step by Step

By the definition of $i$ shown on Page 485, we know that $\sqrt -1=i$ because $i^{2}=-1$. Therefore, $-i^{2}=-(-1)=1$.
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