## Intermediate Algebra (12th Edition)

$r=-2$
$\bf{\text{Solution Outline:}}$ To solve the given radical equation, $\sqrt[3]{r+1}+1=0 ,$ use the properties of equality to isolate the radical expression. Then raise both sides of the equation to the exponent equal to the index of the radical. Then use properties of equality to isolate and solve the variable. Finally, do checking of the solution/s with the original equation. $\bf{\text{Solution Details:}}$ Using the properties of equality to isolate the radical expression results to \begin{array}{l}\require{cancel} \sqrt[3]{r+1}=-1 .\end{array} Raising both sides of the equation to the third power results to \begin{array}{l}\require{cancel} \left( \sqrt[3]{r+1} \right)^3=\left( -1 \right)^3 \\\\ r+1=-1 .\end{array} Using the properties of equality to isolate the variable results to \begin{array}{l}\require{cancel} r=-1-1 \\\\ r=-2 .\end{array} Upon checking, $r=-2$ satisfies the original equation.