Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 7 - Section 7.4 - Adding and Subtracting Radical Expressions - 7.4 Exercises - Page 465: 7

Answer

$7\sqrt 3$

Work Step by Step

$-2\sqrt 48+3\sqrt 75=-2\sqrt (16\times3)+3\sqrt (25\times3)=-2\times\sqrt 16\times\sqrt 3+3\times\sqrt 25\times\sqrt 3=-2\times4\times\sqrt 3+3\times5\times\sqrt 3=-8\sqrt 3+15\sqrt 3=7\sqrt 3$
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