Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 7 - Section 7.4 - Adding and Subtracting Radical Expressions - 7.4 Exercises - Page 465: 10

Answer

$-2\sqrt[3] 3$

Work Step by Step

$3\sqrt[3] 24-2\sqrt[3] 192=3\sqrt[3] (8\times3)-2\sqrt[3] (64\times3)=3\times\sqrt[3] 8\times\sqrt[3] 3-2\times\sqrt[3] 64\times\sqrt[3] 3=3\times2\times\sqrt[3] 3-2\times4\times\sqrt[3] 3=6\sqrt[3] 3-8\sqrt[3] 3=-2\sqrt[3] 3$
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