Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 7 - Section 7.4 - Adding and Subtracting Radical Expressions - 7.4 Exercises: 10

Answer

$-2\sqrt[3] 3$

Work Step by Step

$3\sqrt[3] 24-2\sqrt[3] 192=3\sqrt[3] (8\times3)-2\sqrt[3] (64\times3)=3\times\sqrt[3] 8\times\sqrt[3] 3-2\times\sqrt[3] 64\times\sqrt[3] 3=3\times2\times\sqrt[3] 3-2\times4\times\sqrt[3] 3=6\sqrt[3] 3-8\sqrt[3] 3=-2\sqrt[3] 3$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.