Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 7 - Section 7.3 - Simplifying Radicals, the Distance Formula, and Circles - 7.3 Exercises: 136

Answer

$(x-5)^2+(y+2)^2=16$

Work Step by Step

$\bf{\text{Solution Outline:}}$ Use the Center-Radius Form of the equation of circles to get the equation with the given center, $C( 5,-2 ),$ and the given radius, $r= 4 .$ $\bf{\text{Solution Details:}}$ With the given center, then $h= 5 $ and $k= -2 .$ Using the Center-Radius Form of the equation of circles which is given by $(x-h)^2+(y-k)^2=r^2, $ the equation of the circle is \begin{array}{l}\require{cancel} (x-5)^2+(y-(-2))^2=(4)^2 \\\\ (x-5)^2+(y+2)^2=16 .\end{array}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.