Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 7 - Section 7.2 - Rational Exponents - 7.2 Exercises: 7

Answer

B. 8

Work Step by Step

As shown on page 445, we know that $a^{\frac{m}{n}}=\sqrt[n] a^{m}=(\sqrt[n] a)^{m}$. Therefore, $4^{\frac{3}{2}}=\sqrt[2] 4^{3}=\sqrt 4^{3}=(\sqrt 4)^{3}=2^{3}=8$. We know that $\sqrt 4=2$, because $2^{2}=4$.
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