Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 7 - Section 7.1 - Radical Expressions and Graphs - 7.1 Exercises: 72

Answer

$|k^{5}|$

Work Step by Step

We know that $\sqrt[4] k^{20}=|k^{5}|$, because $(k^{5})^{4}=k^{5\times4}=k^{20}$. Since $k$ is being raised to an odd positive power, we must use an absolute value sign to guarantee that the result is not negative (because $k^{5}$ is negative when $k$ is negative, and we know that there is no real number solution to $\sqrt[n] a$ when $a$ is negative and $n$ is even).
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.