## Intermediate Algebra (12th Edition)

$\frac{4}{3}$
We know that $\sqrt[3] \frac{64}{27}=\frac{4}{3}$, because $(\frac{4}{3})^{3}=\frac{4}{3}\times\frac{4}{3}\times\frac{4}{3}=\frac{4\times4\times4}{3\times3\times3}=\frac{64}{27}$.