Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 7 - Section 7.1 - Radical Expressions and Graphs - 7.1 Exercises: 15

Answer

6

Work Step by Step

We know that $\sqrt[3] 216=6$, because $6^{3}=6\times6\times6=216$.
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