## Intermediate Algebra (12th Edition)

Published by Pearson

# Chapter 7 - Section 7.1 - Radical Expressions and Graphs - 7.1 Exercises: 8

B. 8

#### Work Step by Step

We know that $\sqrt 64=8$, because $8^{2}=8\times8=64$. We also know that $\sqrt 81=9$, because $9^{2}=9\times9=81$. Therefore, $\sqrt 67.8$ must be between 8 and 9. Since \$|67.8-64|

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