Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 6 - Section 6.2 - Adding and Subtracting Rational Expressions - 6.2 Exercises: 30

Answer

$(y-4)^{2}(y+4)$

Work Step by Step

We are given the denominators $y^{2}-16$ and $y^{2}-8y+16$. In order to find the least common denominator, we must factor each denominator. $y^{2}-16=(y+4)(y-4)$ $y^{2}-8y+16=(y-4)(y-4)=(y-4)^{2}$ Next, we multiply together all distinct factors from each denominator, with each factor raised to the greatest power that occurs in any denominator. $LCD=(y-4)^{2}\times(y+4)=(y-4)^{2}(y+4)$
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