Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 6 - Section 6.2 - Adding and Subtracting Rational Expressions - 6.2 Exercises: 19

Answer

$\frac{5}{p+3}$

Work Step by Step

$\frac{-3p+7}{p^{2}+7p+12}+\frac{8p+13}{p^{2}+7p+12}=\frac{-3p+7+8p+13}{p^{2}+7p+12}=\frac{5p+20}{p^{2}+7p+12}=\frac{5(p+4)}{(p+3)(p+4)}=\frac{5}{p+3}\times\frac{p+4}{p+4}=\frac{5}{p+3}\times1=\frac{5}{p+3}$
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