Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 6 - Section 6.2 - Adding and Subtracting Rational Expressions - 6.2 Exercises: 16

Answer

2

Work Step by Step

$\frac{6y+12}{4y+3}+\frac{2y-6}{4y+3}=\frac{6y+12+2y-6}{4y+3}=\frac{(6y+2y)+(12-6)}{4y+3}=\frac{(8y)+(6)}{4y+3}=\frac{8y+6}{4y+3}=\frac{2}{1}=2$
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