Answer
$-\frac{2}{x^{3}}$
Work Step by Step
$\frac{9}{4x^{3}}-\frac{17}{4x^{3}}=\frac{9-17}{4x^{3}}=\frac{-8}{4x^{3}}=\frac{-8\div4}{4x^{3}\div4}=-\frac{2}{x^{3}}$
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