Answer
$-(x+2)$
Work Step by Step
$\frac{x^{2}-4}{2-x}=\frac{(x+2)(x-2)}{2-x}=\frac{(x+2)(x-2)}{-(x-2)}=\frac{x+2}{-1}\times\frac{x-2}{x-2}=-(x+2)\times1=-(x+2)$
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