Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 6 - Section 6.1 - Rational Expressions and Functions; Multiplying and Dividing - 6.1 Exercises: 41

Answer

$\frac{2}{t-3}$

Work Step by Step

$\frac{2t+6}{t^{2}-9}=\frac{2(t+3)}{(t+3)(t-3)}=\frac{2}{t-3}\times\frac{t+3}{t+3}=\frac{2}{t-3}\times1=\frac{2}{t-3}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.